Hello! Are you ready for an exciting voyage into the wonderful realm of strings and data structures? Today, we will assist Alice, an aspiring cryptographer, with an intriguing string manipulation task. She loves playing with strings and has come up with a unique string encoding scheme. I assure you, this will be an enlightening journey that will stretch your programming muscles. Let's get started!

Alice has devised a unique way of encoding words. She takes a word and replaces each character with the next character in the alphabetical order. In other words, given a string word, for each character, if it is not z, she replaces it with the character that comes next alphabetically. For the character z, she replaces it with a.

Another element of Alice's algorithm involves frequency analysis. After shifting the characters, she counts the frequency of each character in the new string. Then, she creates an association between each character with its frequency and ASCII value. Each character maps to a number, which is a product of the ASCII value of the character and its frequency. Our task is to construct a list containing these products, sorted in descending order.

Example

For the input string "banana", the output should be [294, 222, 99].

The string "banana" will be shifted to "cbobob".

Calculating the product of frequency and ASCII value for each character:

• The ASCII value for c is $99$; it appears once in the string, so its product is $99 \cdot 1 = 99$.
• The ASCII value for b is $98$; it appears three times in the string, so its product is $98 \cdot 3 = 294$.
• The ASCII value for o is $111$; it appears twice in the string, so its product is $111 \cdot 2 = 222$.

Collecting these products into a list gives [99, 294, 222]. Sorting this list in descending order results in [294, 222, 99].

Our first step involves mapping each character of the input string to the next alphabetical character. We define nextString as a string, storing the shift operation result. We then iterate over each character of the input string. If a character is not z, we replace it with the next alphabetical character. If it is z, we replace it with a.

Here's the updated function in TypeScript:

TypeScript
Copy to clipboard
1function characterFrequencyEncoding(word: string): string {
2    let nextString: string = '';
3    for (let i = 0; i < word.length; i++) {
4        let letter: string = word[i];
5        if (letter === 'z') {
6            nextString += 'a';
7        } else {
8            nextString += String.fromCharCode(letter.charCodeAt(0) + 1);
9        }
10    }
11    return nextString;
12}

The next step is to track the frequency of each character in nextString. We start by initializing an empty object frequencyMap with string keys and number values. Then, we iterate over nextString. If the current character exists in frequencyMap, we increment its frequency by 1. If it doesn't exist, we add it to frequencyMap with a frequency of 1.

Here's the function in TypeScript:

TypeScript
Copy to clipboard
1function countFrequency(nextString: string): Record<string, number> {
2    const frequencyMap: Record<string, number> = {};
3    for (let i = 0; i < nextString.length; i++) {
4        let letter: string = nextString[i];
5        if (frequencyMap[letter]) {
6            frequencyMap[letter]++;
7        } else {
8            frequencyMap[letter] = 1;
9        }
10    }
11    return frequencyMap;
12}

Next, we calculate the numerical representation for each unique character. We define combinedValues as a type of number array to store these numbers. For each character in frequencyMap, we calculate the product of its ASCII representation and its frequency in nextString and append this to combinedValues.

Here's the updated function:

TypeScript
Copy to clipboard
1function buildProductList(frequencyMap: Record<string, number>): number[] {
2    const combinedValues: number[] = [];
3    for (let letter in frequencyMap) {
4        const asciiValue: number = letter.charCodeAt(0);
5        const frequency: number = frequencyMap[letter];
6        combinedValues.push(asciiValue * frequency);
7    }
8    return combinedValues;
9}

The final step is to sort the list combinedValues in descending order using TypeScript's sort method with a custom comparison function.

Here's our complete function:

TypeScript
Copy to clipboard
1function characterFrequencyEncodingComplete(word: string): number[] {
2    // Step 1: Mapping each character to the next alphabetical character
3    let nextString: string = '';
4    for (let i = 0; i < word.length; i++) {
5        let letter: string = word[i];
6        if (letter === 'z') {
7            nextString += 'a';
8        } else {
9            nextString += String.fromCharCode(letter.charCodeAt(0) + 1);
10        }
11    }
12
13    // Step 2: Counting the frequency of characters in nextString
14    const frequencyMap: Record<string, number> = {};
15    for (let i = 0; i < nextString.length; i++) {
16        let letter: string = nextString[i];
17        if (frequencyMap[letter]) {
18            frequencyMap[letter]++;
19        } else {
20            frequencyMap[letter] = 1;
21        }
22    }
23
24    // Step 3: Building the product list
25    const combinedValues: number[] = [];
26    for (let letter in frequencyMap) {
27        const asciiValue: number = letter.charCodeAt(0);
28        const frequency: number = frequencyMap[letter];
29        combinedValues.push(asciiValue * frequency);
30    }
31
32    // Step 4: Sorting the final values in descending order
33    combinedValues.sort((a, b) => b - a);
34
35    // Return the sorted list
36    return combinedValues;
37}
38
39// Testing the function
40const word: string = 'banana';
41const result: number[] = characterFrequencyEncodingComplete(word);
42console.log(result); // Prints: [294, 222, 99]

Well done! You've successfully tackled an intricate problem that required you to exercise multiple topics such as string manipulation, object processing, and array sorting. This task underscored the importance of reusing already calculated values. I encourage you to apply what you've learned today to other tasks. Many more exciting challenges are waiting for you in the upcoming practice sessions. Happy coding!