Mastering Parallel String and Array Manipulations with TypeScript | CodeSignal Learn

Mastering Parallel String and Array Manipulations with TypeScript | CodeSignal Learn

Introduction

Welcome to a new session, where we embark on a journey into the mystical territory of combined string and array operations. Have you ever thought about how to update a string and an array in parallel while a specific condition holds true? That's precisely what we'll explore today, all in the context of a real-world scenario related to a mystery novel book club. Get ready to dive in!

Task Statement

Our mission today is to generate a unique encoded message for a book club. Here's the fun part: to create a cryptic message, we will process a string and an array of numbers simultaneously and stop once a given condition is satisfied. For the string, our task is to replace each letter with the next alphabetical letter and then reverse the entire updated string. For the array of numbers, our task is to divide each number by 2, round the result, and accumulate the rounded numbers until their total exceeds 20 . When the accumulated total exceeds 20, we immediately stop the process and return the updated string and the as-yet-unprocessed numbers in their original order. Example Consider the input string "books" and the array [10, 20, 30, 50, 100] . We start our process with an empty string and a sum of 0 . For the first character'b' in "books", we replace it with the next alphabet'c' . For the corresponding number 10 in the array, we divide it by 2 and round it. The result is 5 . The sum after the first operation is 5, which is less than 20, so we continue to the next character. For the next character'o', we replace it with'p' . For the corresponding number 20 in the array, half and rounded is 10 . The sum after the second operation is 15 (5 + 10). The sum still doesn't exceed 20, so we move to the third character. For the next character'o', we replace it with'p' . For the corresponding number 30 in the array, half and rounded is 15 . When we add this 15 to the previously calculated sum of 15, it totals 30, which is more than 20 . So, we stop the process here. We have processed'b','o', and'o' from the word "books" and replaced them with'c','p', and'p' respectively to get "cpp" . After reversing, we get "ppc" . For the array, we exclude any numbers that we have processed. Hence, we exclude the first three numbers, and the array becomes [50, 100] . So the output should be "ppc 50, 100" .

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Let's begin our journey by setting up two crucial components: our resultant string and a variable to keep track of the cumulative sum. function solution(inputString: string, numbers: number[]): string {let result: string = ''; let sumSoFar: number = 0;

Solution Building: Step 2 - Iteration and Updates

With the setup complete, it's time to roll up our sleeves and process the inputString and the array. We need to iterate over the inputString and update each character to its next alphabetical character. Simultaneously, we'll keep tabs on our array condition — if the sum of half of the numbers crosses our threshold of 20, we should stop the process. function solution(inputString: string, numbers: number[]): string {let result: string = ''; let sumSoFar: number = 0; let i: number = 0; while (i < inputString.length && sumSoFar <= 20) {result += inputString.charAt(i) === 'z' ? 'a' : String.fromCharCode(inputString.charCodeAt(i) + 1); let halfNumber: number = Math.round(numbers[i] / 2); sumSoFar += halfNumber; i++;}

Solution Building: Step 3 - Final Touch-Up and Return

With the updates complete, we're one step away from solving this mystery. We must reverse our string to generate the final encoded message! At the end, we return the processed string and the remaining array as a single concatenated string separated by a space. function solution(inputString: string, numbers: number[]): string {let result: string = ''; let sumSoFar: number = 0; let i: number = 0; while (i < inputString.length && sumSoFar <= 20) {result += inputString.charAt(i) === 'z' ? 'a' : String.fromCharCode(inputString.charCodeAt(i) + 1); let halfNumber: number = Math.round(numbers[i] / 2); sumSoFar += halfNumber; i++;} result = result.split('').reverse().join(''); let remainingNumbers: number[] = numbers.slice(i); return result + ' ' + remainingNumbers.join(', ');} // Example usage let numbers: number[] = [10, 20, 30, 50, 100]; let result: string = solution("books", numbers); console.log(result); // Output: // ppc 50, 100

TypeScript

function solution(inputString: string, numbers: number[]): string {
    let result: string = '';
    let sumSoFar: number = 0;
    let i: number = 0;
    while (i < inputString.length && sumSoFar <= 20) {
        result += inputString.charAt(i) === 'z' ? 'a' : String.fromCharCode(inputString.charCodeAt(i) + 1);
        let halfNumber: number = Math.round(numbers[i] / 2);
        sumSoFar += halfNumber;
        i++;
    }

TypeScript

function solution(inputString: string, numbers: number[]): string {
    let result: string = '';
    let sumSoFar: number = 0;
    let i: number = 0;
    while (i < inputString.length && sumSoFar <= 20) {
        result += inputString.charAt(i) === 'z' ? 'a' : String.fromCharCode(inputString.charCodeAt(i) + 1);
        let halfNumber: number = Math.round(numbers[i] / 2);
        sumSoFar += halfNumber;
        i++;
    }
    result = result.split('').reverse().join('');
    let remainingNumbers: number[] = numbers.slice(i);
    return result + ' ' + remainingNumbers.join(', ');
}

// Example usage
let numbers: number[] = [10, 20, 30, 50, 100];
let result: string = solution("books", numbers);
console.log(result);

// Output:
// ppc 50, 100