Hello there! Are you ready to enhance your Go programming skills with another exciting exercise? In this unit, we are plunging into the world of matrices. More specifically, we'll be transposing a given matrix. Let's dive into this matrix manipulation without delay!

To begin, let's elaborate on the task at hand. You are required to write a Go function named TransposeMatrix(). This function will accept a 2D slice of integers (which represents a matrix) as input. Your responsibility is to return another 2D slice of integers, which is the transposed version of the given matrix.

Remember, when we mention 'transposing a matrix,' we are referring to the process of switching its rows and columns. In other words, all the rows of the original matrix should be converted into columns in the transposed matrix, and vice versa.

For instance, if the original matrix (input 2D slice) is:

Then the transposed matrix (output 2D slice) will be:

It is vital for your result to maintain the integrity of the data type present in the original matrix. The values in the input matrix are integers, and they should be integers in the output matrix as well.

The initial step in building our solution involves determining the dimensions of the matrix. We need to know the number of rows and columns present in it. In Go, you can use the len function to obtain this information. The number of rows is given by len(matrix), and the number of columns by .