Introduction

Welcome back to Multi-Step Percent Problems! With two lessons now behind us, we are at the midpoint of this five-lesson course. In Lesson 1, we practiced choosing the correct base when a problem involves more than one number. In Lesson 2, we learned how to work backward from a final amount to recover the original value before a percent change. Both of those skills feed directly into what comes next.

This third lesson tackles a situation that shows up all the time in everyday life: two percent changes happening one after another. A store runs a 20% sale and then takes an extra 10% off at the register. An investment gains 15% one year and loses 10% the next. In each case, the second percent change does not apply to the starting amount — it applies to whatever the amount became after the first change. Learning to handle these consecutive percent changes correctly is our goal for this lesson.

Why the Base Shifts After Each Step

Every percent change has a base, the number the percent is taken from. When two changes happen in sequence, the base for the second change is the result of the first change, not the starting value.

Think of it like climbing stairs. After the first step, you are standing on a new level. The second step begins from wherever you landed, not back on the ground floor. Percent changes work the same way: each change updates the amount, and the next change starts from that updated amount. Keeping track of this shifting base is the key to getting consecutive percent problems right.

Walking Through Two Consecutive Changes

Let's work through a concrete example. Suppose a jacket is originally priced at $80. The store applies a 25% discount, and then a loyalty program gives an extra 10% off the already-reduced price. What do we actually pay?

Step 1 — Apply the first change. A 25% discount means we pay 75% of the original price:

80×0.75=6080 \times 0.75 = 60

The price drops to $60 after the first discount.

Step 2 — Apply the second change to the updated amount. The extra 10% off is calculated on $60, not on the original $80:

60×0.90=5460 \times 0.90 = 54
Chaining the Multipliers

There is a handy shortcut. Instead of computing the intermediate amount first, you can multiply the individual change factors together in one expression. As a quick refresher, each percent change has a multiplier:

  • A percent increase of rate rr has a multiplier of 1+r1 + r.
  • A percent decrease of rate rr has a multiplier of 1r1 - r.
The Equal-and-Opposite Surprise

Here is a result that catches many people off guard. Suppose a $200 item increases in price by 10% and then decreases by 10%. Common sense might suggest we end up right back at $200. Let's check.

Step 1 — 10% increase:

200×1.10=220200 \times 1.10 = 220

Step 2 — 10% decrease (applied to $220, not $200):

220×0.90=198220 \times 0.90 = 198

The final amount is $198, not $200. We lost $2 along the way! The order does not matter either — if we decrease first and then increase, we get the same result:

Why Equal Opposites Never Cancel

This pattern is not specific to 10% — it holds for every pair of equal-magnitude opposite changes. If the rate is rr expressed as a decimal, the combined multiplier is:

(1+r)(1r)=1r2(1 + r)(1 - r) = 1 - r^2
Conclusion and Next Steps

In this lesson, we learned how to apply consecutive percent changes by treating each step's result as the new base for the next step. We saw that multiplying the individual change factors gives a single combined multiplier that captures the overall effect. We also discovered that equal-size increases and decreases do not cancel out — the combined multiplier (1+r)(1r)=1r2(1 + r)(1 - r) = 1 - r^2 is always less than 1, producing a net loss every time.

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