Move Until Obstacle Game in Scala

Welcome! In today's lesson, we are tackling an exciting task that combines basic operations with numbers and array manipulation. We will implement a "Move Until Obstacle" game using a linear integer array, this time in Scala. Picture yourself as a game developer and prepare to dive into the fun world of creatively solving problems with Scala!

In this "Move Until Obstacle" game, the player begins at the start of a linear array of integers. The number at each position indicates the number of steps a player can move rightward, while an obstacle number is one upon which you can't land. The aim is to move as far right as possible until an obstacle stops you or you reach the array's end.

Your function, solution(numbers: Array[Int], obstacle: Int): Int, needs to tally and return the number of moves needed to reach the array's end without encountering an obstacle. If the player encounters an obstacle, then the function should return the index at which the obstacle lies.

For example, if the function is given the input: numbers = Array(2, 3, 3, 4, 2, 4) and obstacle = 4, it should return 5. This is because the player starts at the 0th index, takes 2 steps as indicated by the number at the 0th index (landing on the 2nd index), and then takes 3 more steps as indicated by the number at the 2nd index, landing on the 5th index, which is the obstacle 4.

If the function is given the input: numbers = Array(4, 1, 2, 2, 4, 2, 2) and obstacle = 2, the output should be 2. The player starts at the 0th index, takes 4 steps, lands on the 4th index, then takes 4 more steps, which brings the player outside the array, so in total the player makes 2 moves.

Our first step is to ensure that we have variables to track the player, i.e., their current position and the moves they've taken so far. We'll call them position and moves, both initialized to 0 with appropriate data types in Scala:

def solution(numbers: Array[Int], obstacle: Int): Int = {
    var position: Int = 0
    var moves: Int = 0

Next, we'll use a while loop to iterate over the array. It continues as long as position is less than the length of the numbers array:

    while (position < numbers.length) {