Mastering Array Traversal and Manipulation in Go

Welcome to today's session on "Mastering Array Traversal and Manipulation in Go". Multidimensional arrays in Go are like an 'apartment building' with floors (the outer array) and apartments on each floor (the inner array). Today, our goal is to enhance your understanding of these 'apartment buildings' and how to effectively manage them using Go's syntax and data structures.

In Go, we create a multidimensional array by defining arrays containing arrays. Let's see how to create and work with 2D arrays.

package main

import "fmt"

func main() {
    // Creating a 2D array
    array := [3][3]int{
        {1, 2, 3},
        {4, 5, 6},
        {7, 8, 9},
    }

    // Printing the 2D array
    for i := 0; i < len(array); i++ {
        for j := 0; j < len(array[i]); j++ {
            fmt.Print(array[i][j], " ")
        }
        fmt.Println()
    }
}

/*
Prints:
1 2 3 
4 5 6 
7 8 9 
*/

Indices in Go arrays, like in many programming languages, are 0-based. To access a specific element, we specify the indices. For example, visiting the apartment on the second floor (index 1) and delivering a package to the first unit (index 0):

package main

import "fmt"

func main() {
    array := [3][3]int{
        {1, 2, 3},
        {4, 5, 6},
        {7, 8, 9},
    }

    // Accessing an element
    fmt.Println(array[1][0]) // Outputs: 4
}

We've accessed the element 4 in the array by its row and column indices.

In Go, to determine the number of rows (floors) and columns (apartments per floor), we use the len function, which returns the length of an array dimension.

package main

import "fmt"

func main() {
    array := [3][3]int{
        {1, 2, 3},
        {4, 5, 6},
        {7, 8, 9},
    }

    // Finding the number of rows
    numFloors := len(array)
    fmt.Println(numFloors)  // Outputs: 3

    // Finding the number of columns
    numUnits := len(array[0])
    fmt.Println(numUnits)  // Outputs: 3
}