Welcome! Today, I am excited to guide you through an intriguing task involving arrays: pairing up 'opposite' elements. We're going to learn about accessing and manipulating elements in Scala arrays. This task provides an excellent opportunity to refine your array-handling skills in Scala. Are you ready to start? Let's dive right in!

Our task is to form pairs of 'opposite' elements in a given array of integers. In an array of n elements, we view the first and last elements as 'opposite', the second and second-to-last elements as 'opposite', and so on. If the array length is odd, the middle element is its own 'opposite'.

You are provided with an array of n integers, with n ranging from 1 to 100, inclusive. The task necessitates that you return an array of tuples, where each tuple comprises a pair of an element and its 'opposite' element.

For example, for numbers = Array(1, 2, 3, 4, 5, 6, 7), the output should be solution(numbers) = Array((1, 7), (2, 6), (3, 5), (4, 4), (5, 3), (6, 2), (7, 1)).

Before we start writing code, let's familiarize ourselves with how to access the elements of an array in Scala.

In Scala, the i-th element of an array numbers can be accessed as , with the index starting from . Consequently, the first element can be accessed using , the second using , and so forth, up to for the last element.