Greetings! Welcome to our lesson today, where we'll be taking a deep dive into an intriguing aspect of array manipulation. Have you ever considered the idea of traversing an array not from start to end or from end to start, but from the middle, extending towards both ends simultaneously? Today's lesson is all about this concept. Trust me, it's going to be fascinating! Let's jump right in.

Our task is as follows: Given an array of integers, we aim to return a new array that emerges from the center of the original array and alternates direction towards both ends. In other words, the first element of our new array will be the middle element of the original one. After establishing the starting point, we will alternate between the elements to the left and to the right of the initial center until we have incorporated every element. If the length of the initial array is even, we first take the the element to the left of the center, then the one to the right of the center, then do the alternation as described above.

For example, for numbers = [1, 2, 3, 4, 5], the output should be [3, 2, 4, 1, 5].

This task might initially seem complex. However, don't worry. We're going to break it down and construct our solution step by step. Keep in mind an additional condition: the length of the array—represented as n—can vary from 1 to 100,000, inclusive.

To start, we need to establish the middle point of our array. Why the middle, you ask? Well, our task necessitates that we traverse the array from the center to the ends. Python's integer division operator, , allows us to determine the middle. If the array has an odd length, we add the middle element to the array (as it's not paired with any other element), otherwise we keep it empty for now.