Pairing Opposite Elements in Java ArrayLists

Welcome! Today, I am thrilled to guide you through a fascinating task involving ArrayLists in Java: pairing up 'opposite' elements. Specifically, we're going to learn how to access and manipulate elements within a Java ArrayList. The task at hand provides an excellent opportunity to elevate your ArrayList-handling skills within the Java language. Are you ready to get started? Let's dive right in!

Our task today is to form pairs of 'opposite' elements in a given ArrayList of integers. In an ArrayList consisting of n elements, the first and last elements are known as 'opposite', the second element and the second last element are considered 'opposite', and so on. For an ArrayList with an odd length, the middle element is its own 'opposite'.

You will be provided with an ArrayList of n integers. The value of n could range from 1 to 100, inclusive. The task will require you to return an ArrayList of String objects. Each String will consist of an element and its 'opposite' element joined by a space.

Let's use the example ArrayList numbers as {1, 2, 3, 4, 5} to simplify our understanding. In this case, the output of our solution(numbers) function will be {"1 5", "2 4", "3 3", "4 2", "5 1"}.

Before we start writing code, let's familiarize ourselves with how to access the elements of an ArrayList in Java.

In Java, the i-th element of an ArrayList numbers can be accessed as numbers.get(i), with the index starting from 0. Consequently, the first element is numbers.get(0), the second one is numbers.get(1), and so forth, up to numbers.get(numbers.size() - 1) for the last element.

import java.util.ArrayList;

public class Solution {
    public static ArrayList<String> solution(ArrayList<Integer> numbers) {
        int i = 0;
        int elementAtGivenIndex = numbers.get(i);

Now, let's figure out how to access an element's 'opposite'.

The 'opposite' of the i-th element of the ArrayList is the element at the numbers.size() - i - 1-th position. To illustrate this concept, consider standing at the start of a line and your friend standing at the end of the line. In this scenario, you and your friend could be considered 'opposites'. Similarly, the 'opposite' of numbers.get(0) is numbers.get(numbers.size() - 0 - 1), the 'opposite' to numbers.get(1) is numbers.get(numbers.size() - 1 - 1), and so forth.

Now that we understand how to locate an element's 'opposite', we can proceed to code our solution. Let's start by initializing an empty ArrayList named result to store our 'opposite' pairs and compute the ArrayList's size for future reference.

import java.util.ArrayList;

public class Solution {
    public static ArrayList<String> solution(ArrayList<Integer> numbers) {
        ArrayList<String> result = new ArrayList<>();
        int n = numbers.size();