Using Nested Loops and Lists to Retrieve Integer Pairs in Kotlin

Welcome to our programming practice lesson! Are you ready for a challenging yet exciting task involving nested loops and arrays? We will be unraveling the skill of using nested loops to search through two arrays. Brace yourself for a remarkable journey of practical learning. Let's get started!

Imagine a scenario where you are given two lists of integers. Your task is to write a function that retrieves and returns pairs of integers. The first item of the pair will be from the first list, while the second one will come from the second list. It's crucial to remember that the first element must be less than the second.

The sequence of pairs in your output should align with the order they appear in the input lists. For instance, given the lists {1, 3, 7} and {2, 8, 9}, the function should return {"1 2", "1 8", "1 9", "3 8", "3 9", "7 8", "7 9"}. It will pose a challenge if no pairs exist or if any input list is empty. Let's delve into this task step by step to uncover the solution!

Before venturing into the code, let's decode the problem. Nested looping fits perfectly here.

Start by creating an empty MutableList named result to store our pairs.

fun retrievePairs(list1: List<Int>, list2: List<Int>): MutableList<String> {
    val result = mutableListOf<String>()

Creating your function and data structure first is a wise strategy!

Now, the focus turns to forming the nested loops. You need to iterate over both lists, and for this, you'll need nested loops. An outer loop will select one element from the first list, and an inner loop will scan through each element of the second list.

fun retrievePairs(list1: List<Int>, list2: List<Int>): MutableList<String> {
    val result = mutableListOf<String>()
    for (i in list1) {
        for (j in list2) {
            // Our logic goes here
        }
    }
    return result
}

In this setup, every element in list1 is represented by i, and for each i, j represents an element in list2.