Nested Loops and Slices in Go

Welcome to our course on Mastering Implementation of Advanced Loops in Go! Are you ready for a challenging yet exciting task involving nested loops and slices? We will be unraveling the skill of using nested loops to search through two slices. Brace yourself for a remarkable journey of practical learning. Let's get started!

Imagine a scenario where you are given two slices of integers. Your task is to write a function that retrieves and returns pairs of integers. The first item of the pair will be from the first slice, while the second one will come from the second slice. It's crucial to remember that the first element must be less than the second; that is, for every {i, j} pair, we want that i < j.

The sequence of pairs in your output should align with the order they appear in the input slices. For instance, given the slices {1, 3, 7} and {2, 8, 9}, the function should return {{1, 2}, {1, 8}, {1, 9}, {3, 8}, {3, 9}, {7, 8}, {7, 9}}. In this case, the output does not include neither the pair {3, 2} nor the pair {7, 2}, because they don't respect the constraint that the first element must be less than the second. It will pose a challenge if no pairs exist or if any input slice is empty. Let's delve into this task step-by-step to uncover the solution!

Before venturing into the code, let's decode the problem. Nested looping fits perfectly here, as we need to to compare each element in slice1 with each element in slice2.

Start by creating an empty slice named result to store our pairs. We can use a slice of slices of integers for this purpose.

package main

func solution(slice1 []int, slice2 []int) [][]int {
    result := [][]int{}
    // More implementation will follow
}

Creating your function and data structure first is a wise strategy!

Now, the focus turns to forming the nested loops. You need to iterate over both slices, and for this, you'll need nested loops. An outer loop will select one element from the first slice, and an inner loop will scan through each element of the second slice.

package main

func solution(slice1 []int, slice2 []int) [][]int {
    result := [][]int{}
    for _, i := range slice1 {
        for _, j := range slice2 {
            // Our logic goes here
        }
    }
    return result
}

In this setup, every element in slice1 is represented by i, and for each i, j represents an element in slice2.