Welcome to a new session, where we are embarking on a journey into the mystical territory of combined string and list operations. Have you ever thought about how to update a string and a list in parallel while a specific condition holds true? That's precisely what we'll explore today, all in the context of a real-world scenario related to a mystery novel book club. Get ready to dive in!
Our mission today is to generate a unique encoded message for a book club. Here's the fun part: to create a cryptic message, we will process a string and a list of numbers simultaneously and stop once a given condition is satisfied.
For the string, our task is to replace each letter with the next alphabetical letter and then reverse the entire updated string. For the list of numbers, our task is to divide each number by 2, round the result, and accumulate the rounded numbers until their total exceeds 20.
When the accumulated total exceeds 20, we immediately stop the process and return the updated string and the as-yet-unprocessed numbers in their original order.
Example
Consider the input string "books" and the list listOf(10, 20, 30, 50, 100).
We start our process with an empty string and a sum of 0.
- For the first character
'b'in"books", we replace it with the next alphabet'c'. For the corresponding number10in the list, we divide it by2and round it. The result is5. The sum after the first operation is5, which is less than20, so we continue to the next character. - For the next character
'o', we replace it with'p'. For the corresponding number20in the list, half and rounded is10. The sum after the second operation is15(5 + 10). The sum still doesn't exceed20, so we move to the third character. - For the next character
'o', we replace it with'p'. For the corresponding number30in the list, half and rounded is15. When we add this15to the previously calculated sum of15, it totals30, which is more than20. So, we stop the process here. - We have processed
'b','o', and'o'from the word"books"and replaced them with'c','p', and'p'respectively to get"cpp". After reversing, we get"ppc". - For the list, we exclude any numbers that we have processed. Hence, we exclude the first three numbers, and the list becomes
[50, 100].
So the output should be "ppc 50, 100".
