Advanced List Manipulation

Lesson Overview

In this practice-oriented lesson, we're building on the foundations from Unit 1 to tackle even more sophisticated Advanced List Manipulation . Having explored fundamental array operations, we'll now focus on algorithmic patterns like the Two-Pointer Technique . Mastering these techniques allows you to navigate and transform Kotlin lists and arrays with optimal time complexity, a skill that is essential for high-level technical interviews.

Quick Example

O(n + m)

Coming Up Next: Exercise Time!

Expanding your toolkit with these advanced patterns is key to becoming proficient in Kotlin and acing your technical interviews. Now that we've transitioned from basic manipulation to structured algorithmic strategies, it's time to dive into the exercises. Focus on understanding the "why" behind the movement of the pointers. Let's proceed to the practice!

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fun mergeSortedArrays(arr1: IntArray, arr2: IntArray): IntArray { val merged = IntArray(arr1.size + arr2.size) var i = 0 // Pointer for arr1 var j = 0 // Pointer for arr2 var k = 0 // Pointer for the result array // Compare elements from both arrays and add the smaller one while (i < arr1.size && j < arr2.size) { if (arr1[i] <= arr2[j]) { merged[k] = arr1[i] i++ } else { merged[k] = arr2[j] j++ } k++ } // If arr1 has remaining elements, add them while (i < arr1.size) { merged[k] = arr1[i] i++ k++ } // If arr2 has remaining elements, add them while (j < arr2.size) { merged[k] = arr2[j] j++ k++ } return merged } fun main() { val array1 = intArrayOf(1, 3, 5, 7) val array2 = intArrayOf(2, 4, 6, 8) val result = mergeSortedArrays(array1, array2) // Printing the result println(result.joinToString(" ")) // Output: 1 2 3 4 5 6 7 8 }